Mercurial Hosting > traffic-intelligence
diff python/tests/moving.txt @ 372:349eb1e09f45
Cleaned the methods/functions indicating if a point is in a polygon
In general, shapely should be used, especially for lots of points:
from shapely.geometry import Polygon, Point
poly = Polygon(array([[0,0],[0,1],[1,1],[1,0]]))
p = Point(0.5,0.5)
poly.contains(p) -> returns True
poly.contains(Point(-1,-1)) -> returns False
You can convert a moving.Point to a shapely point: p = moving.Point(1,2) p.asShapely() returns the equivalent shapely point
If you have several points to test, use moving.pointsInPolygon(points, polygon) where points are moving.Point and polygon is a shapely polygon.
| author | Nicolas Saunier <nicolas.saunier@polymtl.ca> |
|---|---|
| date | Tue, 16 Jul 2013 17:00:17 -0400 |
| parents | 027e254f0b53 |
| children | cd342a774806 |
line wrap: on
line diff
--- a/python/tests/moving.txt Tue Jul 16 01:36:50 2013 -0400 +++ b/python/tests/moving.txt Tue Jul 16 17:00:17 2013 -0400 @@ -49,9 +49,9 @@ >>> Point.distanceNorm2(Point(3,4),Point(1,7)) 3.605551275463989 ->>> Point(3,2).inPolygon([Point(0,0),Point(1,0),Point(1,1),Point(0,1)]) +>>> Point(3,2).inPolygonNoShapely(np.array([[0,0],[1,0],[1,1],[0,1]])) False ->>> Point(3,2).inPolygon([Point(0,0),Point(4,0),Point(4,3),Point(0,3)]) +>>> Point(3,2).inPolygonNoShapely(np.array([[0,0],[4,0],[4,3],[0,3]])) True >>> predictPositionNoLimit(10, Point(0,0), Point(1,1)) # doctest:+ELLIPSIS @@ -70,9 +70,9 @@ True >>> t1[1] (1.500000,3.500000) ->>> t1.getTrajectoryInPolygon(np.array([[0,0],[4,0],[4,3],[0,3]])) +>>> t1.getTrajectoryInPolygonNoShapely(np.array([[0,0],[4,0],[4,3],[0,3]])) (0.500000,0.500000) ->>> t1.getTrajectoryInPolygon(np.array([[10,10],[14,10],[14,13],[10,13]])).length() +>>> t1.getTrajectoryInPolygonNoShapely(np.array([[10,10],[14,10],[14,13],[10,13]])).length() 0 >>> from utils import LCSS